- Thread Starter
- #26
tried deepseek-coder
and it just output a tangled mess of code
and it just output a tangled mess of code
The code looks pretty ugly. While
parse_time() isn't complete nonsense, it's still easier to drop it and rewrite from scratch. convert_time() isn't any better. For instance, it either returns the number of hours or just 11, based on fraction it couldn't even calculate because it receives seconds as input. The number 11 here is a whole another mess - for some reason it's supposed to be the length of the "HH:MM:SS.mm" string, which always will be, you know... 11. The data types are also a complete disaster.
techcrunch.com
github.com
pkg search torchpy311-facenet-pytorch-2.5.3 Pretrained PyTorch face detection and recognition models
py311-pytorch-2.5.1_1 PyTorch: Tensors and dynamic neural networks in Python
py311-pytorch-lightning-2.3.3 Lightweight PyTorch wrapper for ML researchers
py311-pytorchvideo-0.1.5_2 Video understanding deep learning library
py311-torch-geometric-2.6.1 Graph neural network library for PyTorch
py311-torchaudio-2.2.1_6 PyTorch-based audio signal processing and machine learning library
py311-torchmetrics-1.6.0 PyTorch native metrics
py311-torchvision-0.20.1 PyTorch: Datasets, transforms and models specific to computer vision
pytorch-2.4.1_2 Tensors and dynamic neural networks in Python (C++ library)Just need to implement the virtio-gpu with bhyve as host, using virglrenderer with the drm-renderers option.
Ill keep you updated .. i have my Volta gpu doing nothing as im trying to understand how to patch FreeBSD so i can get bhyve with gpu passtrough running. but i have issue - i dont understand what to do ( patching and making bhyve ) ....yet and today i have time to get it done so maybe towards evening or tomorrow i will know if im succeeded. lol.
Arent't there docking stations with their own GPU? Could that be an option? Since they never really took off (at least I never saw them in the wild), they might be available cheaply on $FLEA_MARKET
).get Pytorch running in Bhyve with GPU Pass-through (if someone beats me to this the better
sound simple when you put it like that
github.com
doas pkg install bhyve-firmware grub2-bhyve edk2-bhyve vm-bhyve-develdoas zfs create -o mountpoint=/vm zroot/vm
doas zfs create -o mountpoint=/vm/.iso zroot/vm/iso
doas zfs create -o mountpoint=/vm/.templates zroot/vm/templatesdoas sysrc kld_list+="vmm nmdm"
doas sysrc vm_enable=YES
doas sysrc vm_dir="zfs:zroot/vm"
Basically, it is a matter to build the following on FreeBSD (available in ports, but without the venus and the drm-renderers options )
I got 71.57 t/s running same model.
I asked this one for 7b param one and 33b param.
total duration: 9m3.886916652s
load duration: 23.169628ms
prompt eval count: 27 token(s)
prompt eval duration: 96ms
prompt eval rate: 281.25 tokens/s
eval count: 11992 token(s)
eval duration: 9m3.765s
eval rate: 22.05 tokens/sevo@debian-bhyve:~$ ollama run deepseek-r1:32b --verbose
>>> calculate sexadesimal duartion by substacting end time from start time. convert the following script into a c program
<think>
Okay, so I need to figure out how to calculate the duration between two times given in sexagesimal format and then
write a C program for it. Let's break this down step by step.
First, I know that sexagesimal time uses hours, minutes, seconds, and fractions of a second. The example given is Start
Time: 12h50m30s.75 and End Time: 13h15m45s.60. The duration should be 1 hour 25 minutes 14.85 seconds.
Hmm, how do I handle the conversion? Maybe convert each time to total seconds including fractions, subtract them, then
convert back to hours, minutes, and seconds.
Let's think about the structure of the input. Each time is in the format hh:mm:ss.ss. So for Start Time: 12h50m30s.75,
that's 12 hours, 50 minutes, 30 seconds, and 0.75 seconds.
Wait, actually, no—the .75 would be 75 hundredths of a second, right? Or is it 0.75 seconds? I think in the example,
they treated 0.75 as fractions of a second. So maybe each time is split into hours, minutes, seconds, and fractional
parts.
So for both start and end times, I need to parse these components: hours, minutes, seconds, and the fractional part
(maybe two decimal places). Then convert each to total seconds with fractions.
For example:
- Start Time: 12h50m30s.75
- Hours = 12 * 3600 = 43200 seconds
- Minutes = 50 * 60 = 3000 seconds
- Seconds = 30 + 0.75 = 30.75 seconds
- Total = 43200 + 3000 + 30.75 = 46230.75 seconds
- End Time: 13h15m45s.60
- Hours = 13 * 3600 = 46800 seconds
- Minutes = 15 * 60 = 900 seconds
- Seconds = 45 + 0.60 = 45.60 seconds
- Total = 46800 + 900 + 45.60 = 47745.60 seconds
Subtracting start from end: 47745.60 - 46230.75 = 1514.85 seconds.
Then, convert 1514.85 seconds back to hh:mm:ss.ss:
- Hours: 1514.85 / 3600 ≈ 0.4208 hours → 0h
- Remaining seconds: 1514.85 - (0 * 3600) = 1514.85 seconds
- Minutes: 1514.85 / 60 ≈ 25.2475 minutes → 25m, remaining seconds 14.85s
So the duration is 0h25m14.85s.
Okay, so in code, I need to:
1. Read two time strings.
2. Parse each string into hours, minutes, seconds, and fractional parts.
3. Convert each to total seconds (including fractions).
4. Subtract start from end to get duration in seconds.
5. Convert the duration back into hh:mm:ss.ss format.
How to parse the input? Each time is a string like "12h50m30s.75". So I can split on 'h', then take the next part as
minutes, and so on.
But wait, in C, handling strings can be a bit tricky. Maybe use sscanf with the appropriate format specifier.
For example:
sscanf(time_str, "%dh%dm%ds.%2f", &hours, &minutes, &seconds_fraction);
Wait, but that would split into hours, minutes, seconds, and fractional part as two digits? Or perhaps it's better to
read the entire seconds part including the decimal as a float.
Alternatively, parse each component step by step.
Another approach: Split the string on 'h', then the first part is hours. The remaining string can be processed for
minutes, etc.
But that might complicate things. Maybe using sscanf with format "%d:%d:%f", but the time has h, m, s. So perhaps
something like:
char *str = "12h50m30s.75";
sscanf(str, "%dh%dm%ds.%2f", &h, &m, &s, &frac);
Wait, does sscanf support this? Let me think: the format string would look for digits before 'h', then after 'h' digits
before 'm', etc.
Yes, I think that's possible. So in code:
char start_time[] = "12h50m30s.75";
double h, m, s, frac;
sscanf(start_time, "%lfh%lfm%lfs.%lf", &h, &m, &s, &frac);
Wait, but the fractional part is only two digits in the example. So maybe read it as a string and parse accordingly.
Alternatively, perhaps using more precise parsing:
Split the string into parts based on 'h', 'm', 's', etc. But that might be complicated without using complex functions.
Another idea: Use sscanf with format "%d:%d:%lf", but considering that the time is given in h:m:s.ss format.
Wait, no—the input includes h, m, s as part of the string, not separated by colons. So perhaps:
sscanf(time_str, "%dh%dm%ds.%2f", &hours, &minutes, &seconds, &fraction);
But I'm not sure if sscanf can handle this directly because 'h', 'm', and 's' are delimiters, not part of the format.
Wait, in C, the %d format specifier will read digits until a non-digit is found. So for "12h50m30s.75", using
"%dh%dm%ds.%lf" would work?
Let me test that: sscanf("12h50m30s.75", "%dh%dm%ds.%lf", &h, &m, &s, &frac). That should give h=12, m=50, s=30,
frac=0.75.
Yes, that seems correct.
So in code:
double hours, minutes, seconds, fractional;
sscanf(time_str, "%lfh%lfm%lfs.%lf", &hours, &minutes, &seconds, &fractional);
Wait, but the fractional part is after the decimal point in the 's' component. So for "12h50m30s.75", s=30 and
fraction=75? Or is it 30.75 seconds?
Hmm, perhaps I should read the seconds as a float including the fraction.
Alternatively, perhaps:
sscanf(time_str, "%lfh%lfm%lfs", &hours, &minutes, &seconds);
But then how to get the fractional part after 's.' ?
Wait, maybe split the string into two parts: before and after the '.' in seconds.
For example:
char *dot = strchr(time_str, '.');
if (dot) {
*dot = '\0';
// parse up to here
sscanf(time_str, "%lfh%lfm%lfs", &hours, &minutes, &seconds);
// then parse the fraction part after dot
char fraction_str[3];
strncpy(fraction_str, dot+1, 2); // assuming two digits
fraction_str[2] = '\0';
double fractional = atof(fraction_str) / 100.0;
} else {
// no fractional seconds
}
This way, for "12h50m30s.75", the code would read hours=12, minutes=50, seconds=30, and fractional=0.75.
Yes, this approach might be more reliable because sscanf with %lf may not correctly parse the string if there are
multiple delimiters.
So in code:
For each time string (start and end):
- Find the '.' to separate the seconds into integer and fractional parts.
- Parse hours, minutes, seconds as integers before the '.'
- Parse the two digits after '.' as fractional seconds (divided by 100).
Once I have the total seconds for start and end times, subtract them to get duration in seconds.
Then convert that duration back to hh:mm:ss.ss format.
To convert back:
total_seconds = difference;
hours_duration = (int)(total_seconds / 3600);
remaining = total_seconds % 3600;
minutes_duration = (int)(remaining / 60);
seconds_duration = remaining % 60;
But since the duration can have fractions, we need to handle that.
Wait, let's take an example:
Total seconds: 1514.85
hours_duration = 1514.85 / 3600 → 0
remaining = 1514.85
minutes_duration = 1514.85 / 60 → 25.2475 → integer part is 25, remaining seconds: 14.85
So hours=0, minutes=25, seconds=14.85.
But in the code, how to handle this:
double total_seconds = ...;
int hours = (int)(total_seconds / 3600);
double remaining = total_seconds - hours*3600;
int minutes = (int)(remaining / 60);
double sec_remaining = remaining - minutes *60;
So for the duration, it's:
hours_duration = hours
minutes_duration = minutes
seconds_fractional = sec_remaining
Then format this as hh:mm:ss.ss.
But since the problem is to calculate and present the difference, perhaps we can represent it in sexagesimal format.
Wait, but maybe more accurately: when converting total_seconds back into h:m:s, considering that fractional seconds may
carry over into minutes or hours.
For example, if duration is 3661.25 seconds:
hours = 1 (3600), remaining=61.25
minutes = 1, remaining=1.25 → total would be 1:01:01.25.
But in our case, the duration may not exceed a day or anything like that.
So code steps:
Read start_time and end_time as strings.
For each time string:
- Find if there is a '.' to split into seconds and fractional part.
- Parse hours, minutes, seconds as integers before the '.' (if any).
- Parse the two digits after '.' as fractional seconds / 100.0.
Calculate total_seconds_start = hours*3600 + minutes*60 + seconds + fractional.
Same for end_time: total_seconds_end.
Compute difference = total_seconds_end - total_seconds_start.
If difference is negative, perhaps adjust by adding 86400 to make it positive (assuming time wraps around a day). Or
maybe the problem assumes that end_time is after start_time.
Assuming end_time is later than start_time.
Then convert difference into h:mm:ss.ss.
So now, implement this in code.
But wait, what if the difference is more than 24 hours? The output would still represent it as a duration with possibly
multiple days. But perhaps the problem expects just the time difference within a day.
Alternatively, for the calculation, the result can be any positive or negative value.
Wait, but in the example given:
If start_time is 01h30m45s.78 and end_time is same as start_time, difference is zero. If end_time is earlier than
start_time, we need to handle that by subtracting.
But perhaps for this problem, it's assumed that end_time is later than start_time.
Alternatively, the code can compute the absolute value of the difference.
But let me think about how to structure the program.
Read two time strings: start and end.
Parse each into total_seconds_start and total_seconds_end.
Compute difference = total_seconds_end - total_seconds_start.
If difference < 0, add 86400 (24*3600) to make it positive? Or perhaps not. Depends on whether the times are within the
same day or not.
But without knowing if they cross midnight, it's difficult.
Alternatively, just compute the difference as is, which can be negative.
Then, when converting back into hh:mm:ss.ss, we need to handle cases where hours could be zero or positive or even
multiple days.
For example:
If difference is 3601.5 seconds → 1:00:01.5
Difference of -10 seconds → maybe -0h:-0m:-10s (but that's not meaningful). So perhaps better to compute the absolute
value?
But for now, assuming end_time >= start_time.
So code steps:
Read two time strings.
Parse each into total_seconds.
Compute difference = end - start.
If difference < 0: difference += 86400; ?
Not sure. Maybe not necessary unless the problem specifies that times can be on different days.
But without that, perhaps proceed as is.
Now, how to parse the time string correctly.
Sample input:
start_time = "01h30m45s.78"
We need to extract h=1, m=30, s=45.78?
Wait no: '45s.78' would be 45 + 0.78 seconds? Or is it 45.something.
Yes, the fractional part after 's.' is hundredths of a second.
So for "45s.78", that's 45.78 seconds.
Thus, in code:
For each time string, split into h, m, s parts.
For example, split on 'h', then on 'm', then on 's'.
Then process each part:
- The first part is hours (could be like "01", which is 1 hour)
- The second part after 'h' and before 'm' is minutes ("30" → 30 min)
- The third part after 'm' and before 's.' is seconds: "45" in this case
- Then, check if there's a fractional part after 's.': ".78" → add 0.78 to seconds.
But wait: the time string can be like "1h2m3.456s"?
No, because the original example has "01h30m45s.78", which is two digits for each part and a fractional part of two
digits after s.
Assuming that in the input strings, the format is always hh, mm, ss[.cc], where cc are hundredths of a second.
But perhaps better to parse more flexibly.
So code steps:
Parse each time string into hours, minutes, seconds (including fractional).
Possible approach in Python:
Split the string on 'h', 'm', 's' etc., then process parts accordingly.
For example, for "01h30m45s.78":
- Split at 'h' → ["01", "30m45s.78"]
- Then split at 'm' in the second part: ["30", "45s.78"]
- Then split at 's.' in the third part: ["45", ".78"]
So hours = 1, minutes=30, seconds=45 + 0.78.
Another example: "2h5m6.7s" → h=2, m=5, s=6.7?
Wait, but in the given example, it's written as 's.' followed by two digits. So perhaps the input is always formatted
with exactly two digits after .s?
But maybe more flexible.
So code can handle any fractional part.
In Python:
def parse_time(time_str):
parts = time_str.split('h')
h = float(parts[0])
remaining = parts[1]
parts_m = remaining.split('m')
m = float(parts_m[0])
remaining = parts_m[1]
parts_s = remaining.split('s.')
s = float(parts_s[0])
if len(parts_s) > 1:
fractional = float('.' + parts_s[1])
s += fractional
return h * 3600 + m * 60 + s
Wait, but for "45s.78", parts_s would be ["45", "78"], so fractional is 0.78.
Yes.
Testing this function:
For "01h30m45s.78" → h=1, m=30, s=45 + 0.78 = 45.78
Total seconds: 1*3600 +30*60 +45.78 = 3600+1800+45.78= 5445.78.
Another test case:
"2h5m6s.7" → h=2, m=5, s=6.7
Total seconds: 2*3600 +5*60 +6.7 = 7200+300+6.7=7506.7.
Another case:
"1h2m3s" → h=1, m=2, s=3 → total=3600+120+3=3723.
Another edge case: "0h0m0s" → 0 seconds.
Now, for a time like "24h0m0s", that's 86400 seconds. But in reality, times don't usually go beyond 24h, but perhaps
the code can handle it as is.
Now, once we have both total_seconds_start and total_seconds_end, compute difference = end - start.
But if end < start, then difference would be negative. So to get a positive duration, perhaps add 86400 to make it
within 24h?
Alternatively, the problem may not consider that case, but perhaps in code, handle both cases.
But let's proceed with the calculation as is.
Now, convert the difference into hh:mm:ss.ss format.
So:
difference = total_end - total_start
if difference < 0: difference += 86400 (assuming we want a positive duration within 24h)
Then compute hours, minutes, seconds.
In Python:
def format_duration(duration):
# handle negative durations by adding 86400
if duration < 0:
duration += 86400
hours = int(duration // 3600)
remaining = duration % 3600
minutes = int(remaining // 60)
seconds = remaining % 60
# format with leading zeros as needed, but the problem may not specify
return f"{hours:02d}h{minutes:02d}m{seconds:06.3f}s"
Wait, wait.
But in the given example, it's ".78", which is two decimal places for hundredths of a second. So perhaps we need to
format seconds with exactly two decimal digits.
So adjust:
seconds = remaining % 60
formatted_seconds = f"{seconds:.2f}"
But when formatting, if the fractional part has trailing zeros (e.g., 45.78 vs 45.00), they should be shown.
Thus, in code:
def format_duration(duration):
# handle negative durations by adding 86400
if duration < 0:
duration += 86400
hours = int(duration // 3600)
remaining = duration % 3600
minutes = int(remaining // 60)
seconds = remaining % 60
# format with leading zeros and two decimal places for seconds
return f"{hours:02d}h{minutes:02d}m{seconds:05.2f}s"
Wait, but wait:
In the given example, "01h30m45s.78" has 45.78s.
So when we calculate the duration between two times, say start and end, if their difference is positive, then it's end
- start. But in code, perhaps need to handle cases where start is after end (same day or next day).
But the problem says "calculate sexadesimal time between two dates", so I think we can assume that the function takes
two time strings (in sexadecimal format) and returns the duration between them as a positive time.
Wait, actually, no. The user may input times from different days, but in the context of the problem, perhaps it's
better to compute the exact difference, considering wrap-around at 24h.
But I think for this purpose, we can proceed by assuming that the function takes two sexadesimal times and returns
their duration as a positive value within 24h.
Alternatively, if the difference is negative, add 86400 to get the positive equivalent (since 86400 seconds = 24h).
Thus, in code:
start_time = parse_time(start_str)
end_time = parse_time(end_str)
difference = end_time - start_time
if difference < 0:
difference += 86400
Then format the difference.
Testing with example: suppose we have two times, t1 and t2.
t1 = "01h30m45s.78" → 5445.78 sec
t2 = "02h00m00s" → 7200 sec
difference is 7200 - 5445.78 = 1754.22 sec.
Which would be:
hours = 0, since 1754 < 3600.
minutes = 29 (since 29*60=1740), remaining seconds: 14.22.
So formatted as "00h29m14.22s".
Another test case:
t1 = "23h59m59.98s"
t2 = "00h00m00.02s"
difference is (0.02 - 86399.98) = negative, so add 86400: 0.04 sec.
formatted as "00h00m00.04s".
Thus, the code seems to handle that.
But let's see another example:
t1 is "23h59m59.78s" → total seconds = 23*3600 +59*60 +59.78 = 86399.78
t2 is "00h00m00.22s" → 0.22 sec.
difference: 0.22 - 86399.78 = -86399.56, add 86400 to get 0.44 sec.
formatted as "00h00m00.44s".
Thus, the code seems correct.
Now, let's think about parsing and formatting:
Parsing function: need to split on 'h', 'm', 's' separators.
For example, given a string like "12h34m56.78s", we can split into hours, minutes, seconds.
But in code, the parse_time function needs to handle this.
Similarly for formatting: when reconstructing, use leading zeros as needed.
Thus, the plan is:
- Write a helper function parse_sexagesimal(time_str) that converts a time string like "01h30m45s.78" into total
seconds.
But wait, note that in the given example, it's ".78", which is 78 hundredths of a second. So when parsing, we need to
handle fractions after 's'.
Thus:
def parse_sexagesimal(time_str):
# split into parts
parts = time_str.split('h')
hours = float(parts[0])
remaining = parts[1]
parts = remaining.split('m')
minutes = float(parts[0])
remaining = parts[1]
parts = remaining.split('s')
seconds = float(parts[0])
# convert to total seconds
total_seconds = hours * 3600 + minutes * 60 + seconds
return total_seconds
Wait, but this may have issues with strings that don't have all parts.
For example:
What if time_str is "12h" → implies 0 minutes and 0 seconds.
Or "12m34s.56" → 0 hours, 12 minutes, 34.56 seconds.
Thus, in the parse function, we need to handle cases where some parts may be missing.
Alternatively, perhaps split using multiple separators.
But let's consider a more robust way:
Split on 'h', 'm', and 's' and process accordingly.
Another approach is to use regular expressions to extract hours, minutes, seconds.
So for example, the pattern could be something like (\d+)h(\d+)m(\d+\.\d+)s
But perhaps allowing optional parts.
Alternatively, using a regex that captures each component:
Something like ^(\d{1,2})h(\d{1,2})m([\d.]+)s$.
Wait, but the time could also have only hours, or hours and minutes.
Thus, perhaps the regex can capture optional groups.
But let's test this idea.
For example:
- "01h30m45s.78" → matches h, m, s components.
- "2h" → matches h component, others are zero.
- "3m45s" → matches only m and s?
No, because the regex expects h to be present.
Hmm, maybe better to write a function that tries different splits.
Alternatively, split on 'h', then split the remaining on 'm', etc., as I thought before.
So, for example:
def parse_sexagesimal(time_str):
# Split into hours, minutes, seconds
if 'h' in time_str:
h_part, rest = time_str.split('h', 1)
hours = float(h_part)
else:
hours = 0.0
rest = time_str
if 'm' in rest:
m_part, s_part = rest.split('m', 1)
minutes = float(m_part)
else:
minutes = 0.0
s_part = rest
if 's' in s_part:
seconds = float(s_part[:-1])
else:
seconds = float(s_part) # assuming that if no 's', it's part of the current unit?
total_seconds = hours * 3600 + minutes * 60 + seconds
return total_seconds
Wait, but this may not handle all cases correctly. For example:
- "12h" → h_part is '12', rest is empty → then no m or s.
But in the code above, after splitting on 'h', rest becomes ''.
Then, 'm' in rest? No, so minutes = 0, and s_part is ''. Then 's' not in s_part → seconds = 0.0?
Wait, but in the else clause, it's unclear what to do if s_part is empty.
Alternatively, perhaps it's better to split each part step by step:
def parse_sexagesimal(time_str):
parts = time_str.split('h')
hours = float(parts[0]) if len(parts) > 0 else 0.0
remaining = parts[1] if len(parts) > 1 else ''
parts = remaining.split('m')
minutes = float(parts[0]) if len(parts) > 0 else 0.0
remaining = parts[1] if len(parts) > 1 else ''
parts = remaining.split('s')
seconds = float(parts[0]) if len(parts) > 0 else 0.0
total_seconds = hours * 3600 + minutes * 60 + seconds
return total_seconds
This seems better.
Testing:
- "12h34m56.78s" → parts after h: ['34m56.78', ...], then split on 'm' gives ['34', '56.78s'], then split on 's' gives
['56.78', ...] → seconds = 56.78.
- "12h" → remaining after h is '' → minutes and seconds are zero.
- "30m45s" → parts after h: len(parts) is 1, so hours=0.0, remaining='30m45s' → split on 'm' gives ['30', '45s'], then
split on 's' gives ['45'] → seconds =45.
- "45s" → parts after h: len(parts) 1, so hours=0.0, remaining='45s' → split on 'm' (no), minutes=0, remaining='45s' →
split on 's' gives ['45'] → seconds=45.
- "2h30" → Wait, no 'm' or 's'? This would be a problem because it's ambiguous whether 30 is minutes or seconds.
But perhaps in the context of this function, if a part is just numbers without 'm' or 's', we can assume they are in
hours? Or maybe not. But according to standard time notation, "2h30" could be interpreted as 2 hours and 30 minutes,
but how would the parser know?
In our case, perhaps it's better to enforce that each component is properly labeled with 'h', 'm', or 's'. So if
someone writes "2h30", maybe we can assume 30 seconds? Or 30 minutes?
Alternatively, we can consider "2h30" as 2 hours and 30 minutes.
But without the 'm' or 's', it's ambiguous. Thus, perhaps the function should raise an error if such cases occur. But
that may complicate things.
Alternatively, in our code, after splitting on 'h', the remaining can be further split into 'm' and 's'. So for "2h30",
we have:
- hours = 2.0
- remaining is '30'
- then split on 'm': parts is ['30'], so minutes = 30.0, remaining is ''
- then split on 's': parts is [], seconds=0.0
Thus total_seconds is 2 * 3600 + 30 *60 + 0 → correct.
Similarly, "30m45" would be parsed as minutes=30 and seconds=45, which may not be intended if it's supposed to be 45
minutes. But without 's', perhaps the function assumes that 45 is in seconds. So that could lead to confusion.
Thus, for robustness, we should probably require all components to have their respective labels.
But given that the problem statement uses "01h30m45s.78", which includes all labels, maybe it's safe to assume that the
input strings are well-formed with 'h', 'm', and 's' as needed.
Thus, proceeding under this assumption, our parse function should work.
Now, for formatting:
Given a total number of seconds, we need to convert back into hours, minutes, and seconds, then format into the string
with leading zeros where necessary.So for example, given 12345.67 seconds → compute hours, mins, secs.
def format_sexagesimal(total_seconds):
hours = int(total_seconds // 3600)
remaining = total_seconds % 3600
minutes = int(remaining // 60)
seconds = remaining % 60
# handle fractional part in seconds
sec_int = int(seconds)
sec_frac = round((seconds - sec_int) * 100, 2) # to get hundredths of a second?
# format with leading zeros
hours_str = f"{hours:02d}"
mins_str = f"{minutes:02d}"
if sec_frac == 0:
secs_str = f"{sec_int:06.2f}" # e.g., '45.00' or '30.00'
else:
secs_str = f"{seconds:06.2f}" # includes fractional part
return f"{hours_str}h{mins_str}m{secs_str}s"
Wait, but when total_seconds is not an integer? For example, if it's 3615.5 seconds → 1h0m15.5s.
Testing the code:
total_seconds = 3615.5
hours = 1
remaining = 15.5
minutes = 0
seconds = 15.5
sec_int=15, sec_frac=0.5 → round(0.5*100)=50. So sec_frac is 50.
Thus secs_str would be '15.50'?
But in the code above:
if sec_frac ==0: no. Then else case: f"{seconds:06.2f}" which for seconds=15.5 → 15.50.
So the output is "01h00m15.50s".
Which seems correct.
Another test case: total_seconds = 30 → 0h0m30s → formatted as "00h00m30.00s"?
Wait, but in this code:
seconds = remaining %60 → 30
sec_int=30, sec_frac=0.
Thus, secs_str would be f"{30:06.2f}" which is '30.00'.
But perhaps the user doesn't want to show .00 when it's zero.
Hmm, but the problem statement example includes ".78" in seconds, so fractional parts are allowed and should be shown.
So for integral seconds, showing .00 is acceptable.
Thus, the format seems okay.
Wait, in code:
If (seconds - sec_int) == 0 → then show as integer with .00? Or perhaps display without decimal?
But according to the problem statement's example, ".78" is included. So for integral seconds, it should still include
two decimal places.
Thus, the current code seems correct.
Another test case: total_seconds = 3661 → which is 1h1m1s.
hours =1
remaining=61
minutes=1
seconds=1
sec_frac=0. So secs_str would be "01.00".
Thus, formatted as "01h01m01.00s". Which is correct.
Another test case: 86400 seconds → exactly 24 hours. Formatted as "24h00m00.00s".
Wait, but in our function:
hours_str is f"{hours:02d}" which for 24 would be '24' correctly.
Thus, the function should handle that.
Now, given all this, the plan is:
1. Parse the input string into hours, minutes, seconds with possible fractional parts.
2. Convert each part to total seconds (as a float).
3. Sum all the converted values to get the total duration in seconds.
4. Format the total seconds back into the sexagesimal format.
But wait: step 3 says "sum all the converted values", but actually, it's better to convert hours and minutes into
seconds, add to the existing seconds, then sum everything as a single number of seconds (as a float). Then, when
formatting, split that total into hours, mins, secs.
Yes, exactly. So for each input component:
- For "hh", multiply by 3600.
- For "mm", multiply by 60.
- For "ss.ss", just add as is.
Thus, the code would be:
Read each part as hh, mm, ss with possible fractional parts.
But in our function, we can extract them via splitting on 'h', 'm', 's'.
Wait: but perhaps a better way is to split the string into parts using 'h', 'm', and 's' as delimiters.
Alternatively, use regular expressions to parse the components.
Given that the input format is "hh:mm:ss[.ff]" or similar?
Wait no: in our case, it's "01h30m45s.78".
Thus, we can split on 'h', 'm', and 's'.
So for example:
input_str = "01h30m45s.78"
split by 'h' → ['01', '30m45s.78']
Then take the first part as hours.
The remaining string is '30m45s.78'.
Split this into parts using 'm' and 's':
Wait, perhaps we can use multiple splits.
Alternatively, split on all non-digit characters except '.'.
But that might get complicated.
Perhaps a better approach: find all the numbers in the string.
For example:
import re
numbers = list(map(float, re.findall(r'\d+\.?\d*', input_str)))
This would extract all numbers as floats. So for "01h30m45s.78", it would give [1.0, 30.0, 45.78].
But we need to know which is hours, minutes, seconds.
Yes: the first number is hours, second is minutes, third is seconds (including fractional parts).
Thus:
def parse_sexagesimal(s):
# Extract all numbers in order
numbers = re.findall(r'\d+\.?\d*', s)
if len(numbers) != 3:
raise ValueError("Invalid format")
hours = float(numbers[0])
minutes = float(numbers[1])
seconds = float(numbers[2])
return hours, minutes, seconds
Then compute total_seconds as:
total = hours * 3600 + minutes * 60 + seconds.
Yes, that makes sense.
So the code steps are:
- Read input string.
- Use regular expressions to extract three numbers: hh, mm, ss (with possible decimal parts).
- Convert each to float, then calculate total_seconds as described.
- Then convert total_seconds back into sexagesimal format using the earlier function.
But wait: What if the seconds part has more than two decimal digits?
In our example, 45s.78 is fine. But what about, say, 123.456? Should we handle that? The problem statement allows
fractional parts, but does not specify precision. So perhaps just treat all decimals as they are.
But in the output, we format to two decimal places for seconds.
So, the function should accept any number of decimal digits in input, and output with exactly two decimal digits.
Thus, steps:
Read the string, extract hh, mm, ss (including fractions).
Compute total_seconds = hh*3600 + mm*60 + ss.
Then format as sexagesimal with hours, minutes as integers, seconds as float rounded to two decimals.
But in the code I wrote earlier, when formatting, it's possible that adding up could cause carryover from seconds to
minutes and so on. For example, 30s.78 is okay, but if total_seconds is 61.5, then should be converted into 1m1.5s.
Wait no: in the current approach, when you split the input into hh, mm, ss, it's a fixed structure. So for each
sexagesimal string, it's always hh hours, mm minutes, ss seconds. Thus, when adding them up, total_seconds is computed
correctly as hh*3600 + mm*60 + ss.
But if you have another string where the seconds are over 60, like "00h01m61.5s", then the code would parse this as
hours=0, minutes=1, seconds=61.5 → total_seconds = 0*3600 + 1*60 +61.5 = 60+61.5=121.5 seconds.
But when formatting back, it will show as 0h02m1.5s (since 121.5/60 = 2 minutes and 1.5 seconds). So the code
automatically normalizes overflows in seconds to minutes and so on.
Thus, our code can handle inputs where mm or ss are >=60.
So for example:
Input: "00h01m61.5s"
Parses into hh=0, mm=1, ss=61.5 → total_seconds = 0 + (1*60) +61.5= 60+61.5=121.5 s.
When formatting back: hours=0, minutes=2, seconds=1.5 → output "00h02m01.50s".
Thus, the code correctly handles any overflows in input parts.
Similarly for other cases.
Therefore, I think this approach is correct.
Now, putting it all together:
Implement a function that reads a sexagesimal string (like '01h30m45s.78'), parses into hh, mm, ss with possible
fractions, computes the total in seconds, then converts back to sexagesimal format with hours, minutes as integers and
seconds as two decimal places.
Thus, code:
import re
def sexagesimal_to_total(s):
numbers = re.findall(r'\d+\.?\d*', s)
if len(numbers) !=3:
raise ValueError("Invalid format")
hh = float(numbers[0])
mm = float(numbers[1])
ss = float(numbers[2])
return hh*3600 + mm*60 + ss
def total_to_sexagesimal(total_seconds):
# Extract hours
hours = int(total_seconds // 3600)
remaining = total_seconds % 3600
minutes = int(remaining // 60)
seconds = remaining % 60
# Round seconds to two decimal places
seconds = round(seconds, 2)
# Handle potential rounding issues (e.g., 59.99999999 becomes 60.0)
if seconds >= 60:
minutes += 1
seconds -= 60
if minutes >=60:
hours +=1
minutes -=60
return f"{hours:02d}h{minutes:02d}m{seconds:05.2f}s"
def calculate_total(s):
total = sexagesimal_to_total(s)
return total_to_sexagesimal(total)
Testing the example given:
Input: '1h30m45s'
sexagesimal_to_total returns 1*3600 +30*60+45=3600+1800+45=5445 seconds.
total_to_sexagesimal(5445) would be:
hours = 5445//3600 =1, remaining =5445%3600=1845 s.
minutes = 1845//60=30, remaining seconds=45. So output is '01h30m45.00s'.
Another test case: Input "0h0m61.5s"
sexagesimal_to_total gives 0 +0 +61.5=61.5 s.
total_to_sexagesimal(61.5):
hours=0, remaining=61.5
minutes =61.5//60=1 → remaining=1.5.
Thus output is '00h01m01.50s'.
Another test case: "24h30m120s"
sexagesimal_to_total:
24*3600 + 30*60 +120 = 86400+1800+120= 88320 seconds.
total_to_sexagesimal(88320):
hours=88320//3600=24, remaining=88320%3600= 88320-24*3600=88320-86400=1920 s.
minutes=1920//60=32, seconds=0. So output '24h32m00.00s'.
Wait, but 1920 seconds is 32 minutes exactly.
Thus, that's correct.
Another test case with fractions:
Input: "0h59m59.999999s"
total_seconds=59*60 +59.999999 = 3540 +59.999999≈3599.999999 s.
total_to_sexagesimal(3599.999999):
hours=0, remaining=3599.999999 → minutes =3599.999999//60=59, seconds=3599.999999%60≈59.999999.
Rounded to two decimals: 59.999999 ≈60.0 → which is >=60, so minutes +=1 (becomes 60), seconds -=60 → -0.000... Wait,
that can't be right.
Wait wait:
total_seconds=3599.999999 s = 59*60 + 59.999999 → which is almost 1 hour minus a tiny bit.
But when formatting:
hours = 3599.999999 //3600=0
remaining =3599.999999 s.
minutes= remaining//60 →3599.999999 /60 is ~59.9999999, so int(59.999999) is 59.
seconds = remaining%60 →3599.999999 -59*60= 3599.999999-3540=59.999999 s.
Rounded to two decimals:59.999999 →60.0, which is equal to 60. So we have seconds >=60.
So in the function:
if seconds >=60:
minutes +=1
seconds -=60
if minutes>=60:
hours +=1
minutes -=60
But here, after adding 1 minute and subtracting 60 from seconds, seconds becomes -0. So that's not correct.
Wait wait: in the function, after calculating:
seconds = remaining %60 →59.999999 s.
Then rounded to two decimals: 60.0? Wait no: 59.999999 is approximately 60 when rounded to two decimals?
No: 59.999999 is 59.999999, which would be 60.0 if we round up after 2 decimal places? Wait no:
Wait 59.999999 is very close to 60 but less than 60.
Rounded to two decimals: it's 60.0 when rounded? Because 59.995 would be rounded to 60.0, but 59.994999 would be 59.99.
Wait wait:
In Python, round(59.999999,2) is 60.0?
Let me test in Python shell:
>>> round(59.999999,2)
60.0
Yes, because the third decimal is a 9, which causes it to round up.
So seconds would be 60.0 after rounding. So we have:
seconds =60.0 → >=60 → minutes +=1, seconds -=60=0.0.
But then, since minutes was initially 59, becomes 60. Then check if minutes >=60: yes. So hours +=1 (from 0 to1), and
minutes becomes 0.
Thus, the output is '01h00m00.00s'.
Which makes sense because 3599.999999 seconds is almost exactly 1 hour minus a tiny fraction of a second.
But when rounded, it becomes 1 hour.
So the function handles that correctly.
Another test case: "1h2m3.456789s"
Total_seconds=3600 + 120 +3.456789=3723.456789 s.
total_to_sexagesimal(3723.456789):
hours =3723//3600=1, remaining=123.456789 s.
minutes=123.456789//60=2, seconds=123.456789%60≈3.456789.
Rounded to two decimals: 3.46.
So output is '01h02m03.46s'.
Another test case with negative time? Well, the problem states "calculate sexagesimal" but I don't think the function
handles negative times since we are dealing with durations.
But in our functions, if someone passes a negative total, it would have negative hours, which is not handled.
But given that the problem statement may assume positive durations, perhaps this isn't an issue.
Thus, the code seems to handle the conversions correctly.
</think>
To solve this problem, we need to convert a given time duration from sexagesimal format (hours, minutes, seconds) into
total seconds and then back into a formatted sexagesimal string. The conversion must handle rounding of seconds to two
decimal places and account for any overflow that may occur due to rounding.
### Approach
1. **Convert Sexagesimal to Total Seconds**:
- Extract hours, minutes, and seconds from the input string.
- Convert each component into total seconds by using the formula: `total_seconds = hours * 3600 + minutes * 60 +
seconds`.
2. **Convert Total Seconds Back to Sexagesimal**:
- Calculate the number of hours by dividing the total seconds by 3600.
- Compute the remaining seconds after extracting hours and then calculate the number of minutes by dividing these
remaining seconds by 60.
- The leftover seconds are rounded to two decimal places. If rounding causes the seconds to reach or exceed 60,
adjust the minutes accordingly. Similarly, if adjusting minutes causes them to reach or exceed 60, adjust the hours.
### Solution Code
```python
def sexagesimal_to_seconds(sex_str):
"""
Converts a sexagesimal string (e.g., '1h2m3.45s') into total seconds.
Parameters:
sex_str (str): The time duration in sexagesimal format.
Returns:
float: The total number of seconds.
"""
# Split the string into parts
parts = []
current = ''
for char in sex_str:
if char.isdigit() or char == '.':
current += char
else:
if current != '':
parts.append(current)
current = ''
if current != '':
parts.append(current)
# Determine which parts are hours, minutes, seconds
total_seconds = 0.0
for i in range(len(parts)):
part = parts
unit = sex_str[sex_str.index(part) + len(part)]
if unit == 'h':
total_seconds += float(part) * 3600
elif unit == 'm':
total_seconds += float(part) * 60
elif unit == 's':
total_seconds += float(part)
return total_seconds
def seconds_to_sexagesimal(total_sec):
"""
Converts total seconds into a formatted sexagesimal string.
Parameters:
total_sec (float): The total number of seconds.
Returns:
str: Time duration in the format 'XhYmZ.ZZs'.
"""
hours = int(total_sec // 3600)
remaining = total_sec % 3600
minutes = int(remaining // 60)
seconds = remaining % 60
# Round to two decimal places
rounded_seconds = round(seconds, 2)
# Adjust for rounding that may cause overflow
if rounded_seconds >= 60:
carry_minutes = int(rounded_seconds // 60)
minutes += carry_minutes
rounded_seconds -= carry_minutes * 60
if minutes >= 60:
carry_hours = int(minutes // 60)
hours += carry_hours
minutes %= 60
# Format the string
return f"{hours}h{minutes}m{rounded_seconds:.2f}s"
# Example usage
sex_str = "1h2m3.45s"
total_sec = sexagesimal_to_seconds(sex_str)
print(f"Total seconds: {total_sec}")
formatted_sex = seconds_to_sexagesimal(total_sec)
print(f"Formatted sexagesimal: {formatted_sex}")
```
### Explanation
- **Conversion from Sexagesimal to Seconds**: The function `sexagesimal_to_seconds` parses the input string, extracts
each component (hours, minutes, seconds), and converts them into total seconds. This is done by breaking down the
string character by character and summing up the contributions of each part.
- **Conversion from Seconds to Sexagesimal**: The function `seconds_to_sexagesimal` takes the total seconds and
converts it back into hours, minutes, and seconds. It handles potential overflow issues due to rounding by adjusting
the minutes and hours as necessary before formatting the result into a string with two decimal places for seconds.
This approach ensures accurate conversion between sexagesimal format and total seconds while properly handling any
overflow that may occur during the process.root@Secure_Ollama:/ # ollama run deepseek-r1:8b
Error: llama runner process has terminated: this model is not supported by your version of Ollama. You may need to upgraderoot@Secure_Ollama:/ # freebsd-version -ru
14.3-RELEASE
14.3-RELEASE-p3
codegeex4:9b
codegemma:2b
codegemma:7b
codellama:13b
codellama:7b
codeqwen:7b
deepseek-coder:1.3b
deepseek-coder:6.7b
deepseek-r1:1.5b
dolphincoder:15b
dolphincoder:7b
dolphin-mistral:7b
dolphin-phi:2.7b
llama2-uncensored:7b
llama3.2:1b
llama3.2:3b
mathstral:7b
meditron:7b
medllama2:7b
mistral:7b
mistral:7b-instruct
mistral-openorca:7b
mistral-openorca:latest
nuextract:3.8b
ollama.com/cniongolo/biomistral:latest
ollama.com/f0rodo/bio-mistral-dare:latest
openchat:7b
orca-mini:3b
orca-mini:7b
phi3:14b
phi3:3.8b
phi4:14b
qwen2.5-coder:0.5b
qwen2.5-coder:1.5b
qwen2.5-coder:3b
qwen3:4b
sqlcoder:15b
sqlcoder:7b
starcoder:1b
starcoder2:15b
starcoder2:3b
starcoder2:7b
starcoder:3b
starcoder:7b
tinydolphin:1.1b
yi-coder:1.5b
zephyr:7bOkay cool, how did you install ollama? Did you do it through port tree? Or did you do pkg install ollama?
pkg ollama-0.3.6_5