Running basic commands in a normal user's .cshrc?

[mrjayviper]

Hello. I added a very simple command in a normal user's .cshrc (e.g. /home/my-user-here/.cshrc)

echo "I am here"

It just wouldn't work. If I do the same thing on the root user, it works fine. Any ideas what I could be doing wrong?

Basically my real aim is to automatically run su once I'm logged in using the normal user. And I'm using echo commands for now just as a test.

Thanks

ps. I did try su at first but that didn't work so I then moved to testing using echo commands.

 

[Toast]

If your shell is tcsh(), it will use ~/.tcshrc if it exists instead of ~/.cshrc.

 

[SirDice]

If your shell is tcsh(), it will use ~/.tcshrc instead of ~/.cshrc if it exists.

No, ~/.cshrc will get executed, even with tcsh(1). It's not common to use ~/.tcshrc.

A  login	 shell	 begins	by  executing  commands	 from the system files
       /etc/csh.cshrc and /etc/csh.login.   It	then  executes	commands  from
       files  in  the  user's  home  directory:	 first	~/.tcshrc  (+)	or, if
       ~/.tcshrc is not	found, ~/.cshrc, then ~/.history (or the value of  the
       histfile	shell variable), then ~/.login,	and finally ~/.cshdirs (or the
       value of	 the  dirsfile	shell  variable)  (+).

 

[Toast]

No, ~/.cshrc will get executed, even with tcsh(1).

Edited my previous post as it was worded incorrectly. I meant to say: "If your using tcsh() and ~/.tcshrc exists it will be used instead of ~/.cshrc."

It's not common to use ~/.tcshrc.

As uncommon as it may be, if it exists it would still override ~/.cshrc unless you had

source ~/.cshrc

in it.