/bin/sh: How to parse a date string to variables?

[olav]

I have this string:

2012-04-10_08-00

How can I parse this to year, month and day?

Why wouldn't something like this work?

read Y M D h m s <<< ${timestamp//[-_]/ }

 

[UNIXgod]

<<< is a bashism.

you could translate the hyphen to a newline and loop it in to variables if you need them or just send them to their respective output:

% echo "2012-04-10_08-00" | tr '_-' '\n' 
2012
04
10
08
00

 

[Shamrock]

> cat test.sh 

#!/bin/sh
test=`echo '2012-04-10_08-00' | tr '_-' ' '`
set $(echo $test);
echo $1

> ./test.sh
2012

 

[varda]

# date -f "%Y-%m-%d_%H-%M" 2012-04-10_08-00 "+%Y"
2012
# date -f "%Y-%m-%d_%H-%M" 2012-04-10_08-00 "+%B"
April

DATE="2012-04-10_08-00"; MONTH=$(date -f "%Y-%m-%d_%H-%M" $DATE "+%B")

 

[olav]

Thanks, I finally got this to work