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Old November 10th, 2011, 17:35
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Default BUG? -> sh: [ "$@" ] -> "eats" it's quotes!
If [ "$@" ] is alone, err won't show up, but if you compare it ...

Code:
debug_fun ()
{
    local -
    set -x

    [ "$1" ] && echo '$1 - Empty!'
    [ "$*" ] && echo '$* - Empty!'
    [ "$@" ] && echo '$@ - Empty!'
}


debug_fun_compare ()
{
    local -
    set -x

    [ "$1" = ro ] && echo '$1 - Empty!'
    [ "$*" = ro ] && echo '$* - Empty!'
    [ "$@" = ro ] && echo '$@ - Empty!'
}


debug_fun

debug_fun_compare
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Old November 10th, 2011, 17:53
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Not a bug.

http://www.grymoire.com/Unix/Sh.html#uh-42
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Old November 10th, 2011, 19:06
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Quote:
Originally Posted by SirDice View Post
I know all this and it doesn't give an answer to this.
I'm talking about 0 args here in quotes (as $@ and $*, both behave same, when NOT surrounded with "").
Last edited by DutchDaemon; November 10th, 2011 at 21:40.
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Old November 13th, 2011, 18:23
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[ is expanded like any other simple command. The three tests in your first function are not all expanded the same but all are valid tests returning false. The third test in your second function causes a test(1) syntax error because "$@" expands to nothing at all if there are no positional parameters.
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Old November 13th, 2011, 18:52
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That is exactly, why do I use double quotes around vars, to prevent syntax errors, in case when var isn't set/is undefined.
Problem is, "$@" acts like it was written as $@. It's double quotes disappear (Exposed via set -x in both functions)
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