.include method for unwanted modules list in make.conf

[Beeblebrox]

Very noob scripting (?) question regarding make.conf:

I would like to place my list of unwanted modules (modules not to build) in a separate file so as not to clutter my make.conf. I have placed this file in a sub-dir of /etc. I was hoping that this would do the trick; am I correct?
.include "/etc/make/modexcl.conf"
Where file modexcl.conf has:
WITHOUT_MUDULES= list of mod etc

[SirDice]

I've never tried it but I see no reason why it shouldn't work.

[Beeblebrox]

OK, I'll give it a whirl and post the result.

[Beeblebrox]

Does not work :( In /etc/make.conf
.include "/etc/make/modexcl.amd64.conf"

[ikreos]

Try putting that in src.conf.

http://forums.freebsd.org/showthread.php?t=21258

[Beeblebrox]

So same line exactly
.include "/etc/make/modexcl.amd64.conf"
in src.conf? will try it and post result (later).

EDIT: Tried, with same result - modules listed as exclude were built anyway :(

[Beeblebrox]

WITHOUT_MODULES= "/etc/make/modexcl.conf"
When placed in /etc/make.conf has no effect at all, while the setting below gives error.
.include "/etc/make/modexcl.conf"
line 40: Need an operator.
I have tried variations on modexl.conf as I assume I have not created that file correctly. What would be the correct syntax for such a file?